[最も好ましい] x y=2 2x 2y=4 308362-Y=x^2-2x-4 parabola
X^ {2}2x=y4 Subtract 4 from both sides x^ {2}2x1^ {2}=y41^ {2} Divide 2, the coefficient of the x term, by 2 to get 1 Then add the square of 1 to both sides of the equation This step makes the left hand side of the equation a perfect square x^ {2}2x1=y41Transcribed image text SORU 1(25 puan) (2x – 3y 7) dx = (x – 2y 4) dy diferansiyel denklemin türünü tayin ediniz ve genel çözümünü elde ediniz SORU 2(25 puan) (Siny) (dy/dx) – 2Cosy Cosx Cosx = 0 diferansiyel denklemin türünü tayin ediniz ve genel çözümünü elde ediniz Given 2xy=2 , 2yx=4 To Find the area of a triangle formed by the two lines and the line y=0 Solution 2xy=2 2yx=4 y = 0 2xy=2 , y = 0 => point of intersection ( 1 , 0) 2yx=4 , y = 0 => point of intersection ( 4 , 0) 2xy=2 , 2yx=4 => point of intersection ( 0 , 2) Triangle is formed with base = ( 1 (4) = 5 Height = 2 Solve The Following Systems Of Equations X Y 2 And 2x 2y 4 Brainly In Y=x^2-2x-4 parabola
